100x^2-324x-25=0

Solution for 100x^2-324x-25=0 equation:

100x^2-324x-25=0

a = 100; b = -324; c = -25;
Δ = b2-4ac
Δ = -3242-4·100·(-25)
Δ = 114976
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{114976}=\sqrt{16*7186}=\sqrt{16}*\sqrt{7186}=4\sqrt{7186}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-324)-4\sqrt{7186}}{2*100}=\frac{324-4\sqrt{7186}}{200}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-324)+4\sqrt{7186}}{2*100}=\frac{324+4\sqrt{7186}}{200}
$